3v^2-46v+15=0

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Solution for 3v^2-46v+15=0 equation:



3v^2-46v+15=0
a = 3; b = -46; c = +15;
Δ = b2-4ac
Δ = -462-4·3·15
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-44}{2*3}=\frac{2}{6} =1/3 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+44}{2*3}=\frac{90}{6} =15 $

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